Dilution Problem - Find quantity of solvent

9. Altering Product Strength 9.1) Dilution 9.1.1) Dilution

9.1.1.1) Find initial concentration in dilution Easy 1


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Calculate the quantity of solvent you need to add into 39.5 mL of a 38.25 % solution to prepare a 5.89 % solution?


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lb equals 217 mL kg

    This is a volume expansion or concentration dilution type problem. The essential formula is `Q_1C_1 = Q_2C_2`.
    Here,

    `Q_1` = initial quantity = `39.5\quadmL`.
    `C_1` = initial concentration = `38.25\quad%`
    `Q_2` = final quantity = `?\quad mL`.
    `C_2` = final concentration = `5.89\quad %`

    Therefore, rearranging the formula, we get:
    `Q_2 = (Q_1 × C_1)/(C_2)` `therefore Q_2 = (39.5 × 38.25) /5.89=256.5\quad mL` in nearest whole number.

    Now, subtract the initial quantity of the solution (`39.5\quadmL`) from this final quantity (`256.5\quadmL`) to determine the amount of solvent to be added: `256.5\quadmL-39.5\quadmL=217\quadmL`. (Ans)


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