(type 5) mEq problems - randomized

5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General

5.1.1.1) mEq from weight/volume Normal 1


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A solution contains 200 mg of sodium lactate in each 100 mL (the MW of sodium lactate is 112). Express it as mEq/mL.


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lb equals 0.0179 mEq/mL kg

    The molecular weight of sodium lactate = 112.
    Valence or charge = 1.
    Therefore, we can write: 112 mg = 1 mEq.
    Since the question needs mEq/mL as the final unit, we keep mEq in the starting numerator. So, 112 mg will be the denominator.
    Also, the solution contains 200 mg per 100 mL. In order to cancel out mg, we need to keep 200 mg in the numerator of the second fraction. Therefore, the dimensional analysis will be like this:

    `(1 \quad mEq)/(112 \quad mg) � (200 \quad mg)/(100 \quad mL) =0.0179\quad (mEq)/(mL)` Ans.