### Type 4: Osmolarity of IV solutions (D5W, D5NS, D5½NS)

5. mEq and mOsmol 5.2) mOsmol 5.2.1) mOsmol - General

5.2.1.1) mOsmol - General Hard 1

Total tried:       Correct:       Wrong:

Calculate the total milliosmoles of 15 mL of dextrose 5% solution in water (D5W).

Click on the button below to see the answer and explanations

Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 4.17 mOsmol kg

Dextrose 5% means 5g of dextrose is present in 100 mL. The volume of the solution is 15 mL.
Since it does not dissociate in the solution, for dextrose, we can write the 'golden formula' as:
1\quad mmol=[180] mg = [1] mOsmol.

Using dimensional analysis:

(5 \quad g)/(100 \quad mL) × (1000\quad mg)/(1\quad g) × (1\quad mOsmol)/(180\quad mg) × 15 \quad mL
= 4.17 mOsmol. Ans.

#### 123 ,Lorem Ipsum dummy Text E-mail: [email protected]

Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675