T11: Mixed problems from T1 - T11.
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.2) Clearance
50.1.2.1) Clearance basic concepts Normal 1
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How much drug has to be administered to a patient weighing 75 Kg so that the plasma concentration is 0.35 mg/L? Given that, the Volume of distribution of the drug is 0.47 L/Kg.
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lb equals 12.338 mg kg
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Total volume of distribution (V) for this patient will be:
`0.47 \quad L/(Kg) × 75 \quad Kg = 35.25 \quad L`
Concentration (`C_{0}`) = `0.35 \quad (mg)/L`;
Drug quantity (`X_{0}`) =?
We know that,
`C_{0}=X_{0}/V`
`therefore X_{0} = C_{0} × V`
`= 0.35 \quad (mg)/L × 35.25 \quad L = 12.3375 \quad mg`. Ans.