T20: C0 from AUC and K
50. Pharmacokinetics 50.1) PK Basic parameters 50.1.3) Area Under Curve (AUC)
50.1.3.1) AUC basic concepts Normal 1
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73.04 mg of a drug (elimination rate constant 0.173 h-1) was administered to a patient as an IV push. The plasma concentration over the time (AUC) was found to be 4.62 mg × h/L. Calculate the initial plasma concentration after administration of the drug.
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lb equals 0.8 mg/L kg
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We know that, AUC may be calculated from dose (`X_{0}`) and clearance (`Cl`) OR initial concentration (`C_{0}`) and the elimination rate constant (`K`).
` AUC = (X_{0})/(Cl) = (C_{0})/K`.
By rearranging the equation, we find:
`C_{0}=AUC × K`
`C_{0}=(4.62 \quad mg × h)/L × 0.173 \quad h^{-1} = 0.8 \quad (mg)/L`. Ans.