(type 2) Calculate mEq per volume from mg or percent
5. mEq and mOsmol 5.1) mEq 5.1.1) mEq - General
5.1.1.1) mEq from weight/volume Normal 1
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A solution contains 2.5 mg of potassium carbonate in each 5 mL (the MW of potassium carbonate is 138.2). Express it as mEq/mL.
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lb equals 0.0072 mEq/mL kg
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The molecular weight of potassium carbonate = 138.2.
Valence or charge = 2.
Therefore, we can write: 138.2 mg = 2 mEq.
Since the question needs mEq/mL as the final unit, we keep mEq in the starting numerator. So, 138.2 mg will be the denominator.
Also, the solution contains 2.5 mg per 5 mL. In order to cancel out mg, we need to keep 2.5 mg in the numerator of the second fraction. Therefore, the dimensional analysis will be like this:
`(2 \quad mEq)/(138.2 \quad mg) × (2.5 \quad mg)/(5 \quad mL) =0.0072\quad (mEq)/(mL)` Ans.