### T10) Find elimin. rate from dose, Vd and Cl

50. Pharmacokinetics 50.2) Plasma concentrations over time 50.2.1) Plasma concentrations over time

T01: Later plasma concentration Normal 1

Total tried:       Correct:       Wrong:

A patient is given 88 mg of a drug in IV push. The volume of distribution of the drug in this patient is 20 L. If the clearance is 2.89, then determine the rate of elimination.

Click on the button below to see the answer and explanations

Notice: Undefined variable: input_value1 in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 220
lb equals 12.72 mg/h kg

For rate of elimination (dX/dt), we can write:
(dX)/dt = Cp × Cl

Plasma concentration is obtained by
Cp=X/(Vd)=(88 \quad mg)/(20 \quad L)
\implies (dX)/dt = (88 \quad mg)/(20 \quad L) × 2.89 \quad L/h

∴ (dX)/dt = 12.716 \quad (mg)/h (Ans).

#### 123 ,Lorem Ipsum dummy Text E-mail: [email protected]

Notice: Undefined index: TOTALTRY in /home/jshzub/web/rxcal.org/public_html/practice/practice/includes/body.php on line 675